(3) An analyst processes one item every 30 minutes so 16 items are completed in

(3) An analyst processes one item every 30 minutes so 16 items are completed in her first day of work. Her manager checks her work by randomly selecting an hour of the day then reviewing all the items she completed that hour. Does this sampling plan result in a random sample? Simple random sample?Does this sampling plan result in a random sample?(A) No because each item does not have an equal chance of being selected(B) Yes because each item has an equal chance of being selected(C) No because all possible groups of n items do not have an equal chance of being selected.(D) Yes because all possible groups of n items have an equal chance of being selected.Does the sampling plan result in a simple random sample?(A) No because all possible groups of n items do not have an equal chance of being selected.(B) Yes because each item has an equal chance of being selected(C) Yes because all possible groups of n items have an equal chance of being selected(D) No because each item does not have an equal chance of being selected.(7) (SHOW WORK) A brand name has an 80% recognition rate. If the owner of te brand wants to verify that rate by beginning with a small sample of 10 randomly selected consumers find the probability that exactly 8 of 10 consumers recognize the brand name. Also find the probability that the number who recognize the brand name is XXXXX XXXXXWhat is the probability that exactly 8 of 10 consumers recognize the brand name?What is the probability that the number who recognize the brand name is XXXXX XXXXX?(8) Assume that thermometer readings are normally distributed with a mean of 0 degrees Celsius and a standard deviation of 1 degree Celsius. A thermometer is randomly selected and tested. For the case below draw a sketch and find the probability of the reading. Between -1.11 and 1.59What is the probability of getting a reading between -1.11 and 1.59 degrees Celsius?(9) (SHOW WORK) Womens heights are normally distributed with a mean 63.2 in and a standard deviation of 2.5 in. A social organization for tall people has a requirement that women must be at least 69 in tall. What percentage of women meet that requirement?The percentage of women that are taller than 69 in is ?(10) (SHOW WORK) (A) With n=14 and p=.3 find the binomial probability P(5) by using a binomial probability table. (B) if np is greater than or equal to 5 and nq is less than or equal to 5 also estimate the indicated probability by using the normal distribution as an approximation to the binomial; if np
(a)Find the probability by using a binomail probability table= P(5)=(b) Select the correct choice below and if necessary fill in the answer box to complete your choiceP(5)=the normal distribution cannot be used(11) (SHOW WORK) Using the simple random sample of weights of women from a data set we obtain these sample statistics: n=40 and xbar=142.57 lb. Research from other sources suggests that the population of weights of women has a standard deviation given by o=30.79 lb.a) Find the best point estimate of the mean weight of all womenb) Find a 99% confidence interval estimate of the mean weight of all women(12) Find the critical z values. Assume that the normal distribution applies.Two tailed test; a=.02z= (13) Identify the type 1 error and the type II error that correspond to the given hypothesesThe percentage of high school students who graduate is greater than 55%Type I is?a) reject the null hypotheses that the percentage of high school students who graduate is equal to 55% when that percentage is actually equal to 55%b) fail to reject the null hypothesis that the percentage of high school students who graduate is equal to 55% when that percentage is actually greater than 55%c) Reject the null hypotheses that the percentage of high school students who graduate is greater than 55% when that percentage is actually greater than 55%d)Fail to reject the null hypotheses that the percentage of high school students who graduate is greater than 55% when the percentage is actually equal to 55%Type II is? abcd?