##(a) 4.42s##
##(b) 55.25m##
##(a)##
We get the time taken to reach the maximum height by using the vertical component of the velocity:
##v=u+at##
##:.0=25sin60-9.8t##
##:.t=61.65/9.8=2.21s##
By inference the return to earth will take the same time assuming a level playing field.
##:. ## total time in flight ##=2xx2.21=4.42s##
##(b)##
The horizontal component of velocity is constant so we get:
Distance = speed x time
##=25cos60xx4.42=55.25m##