Brepresents the number of moles of NaOH added at the specific point in the titra

Brepresents
the number of moles of NaOH added at the specific point in the titration so bis equal to the number of moles of
NaOH present at a certain pH and is calculated using C=b*v rearranged to c*v=b.
c= concentration of NaOH and v=volume of NaOH added at that point.Arepresents
the number of moles of the initial acid in the beaker and is calculated by;
c*v=a. C is the concentration of the
acid and v is the volume=0.04*0.025=0.001 moles.The data was then plotted as a graph for pH against Log10(b/a-b);The slope and intercept can then be calculated to deduce
the pH of the solution when x=0 to give the pKaof the benzoic acid.Y=MX+CM=y2-y1/x2-x1 C=y1-mx1Y2 was the highest pH plotted and y1 the lowest pH record;
x2 and x1 are the corresponding log(b/a-b) values.M=(4.5-2.52)/((-0.0872)-(-1.28))=1.66C=(2.52)-(1.66)*(-1.28)=4.54Y=1.66*0+4.54=4.54Therefore; pKaof benzoic acid is 4.54