From the top of a lighthouse 55 ft above sea level the angle of depression to a small boat is 11.3 degrees. How far from the foot of the lighthouse is the boat?

Let ##a## be the altitude of the lighthouse above sea level ##a=55 ft## and ##b## the distance of the boat from the foot of the lighthouse ##thetad = 11.3^0##
Solution:
##tan11.3^0 = 55/x##
##x = 55/(tan11.3^o) = 55/(0.19982)= 275.25 ft. ->Answer
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