Given the right trapezoid calculate angle theta and the area of triangle hat(EAD) provided EA=4 AB=BC=CD=DA=2 AB_|_EC?

##/_theta = arctan((sqrt(3)-1)/2)~~0.350879411 rad##
##S_(EAD) = 2##
From right triangle ##Delta ABE## knowing hypotenuse ##AE=4## and cathetus ##AB=2## we can find another cathetus:
##BE=sqrt(4^2-2^2)=sqrt(12)=2sqrt(3)##.
In the right triangle ##Delta DCE## cathetus ##CD=2##. Second cathetus ##CE = CB+BE = 2+2sqrt(3)##
Now we can determine tangent of angle ##/_ theta##:
##tan(theta) = (CD)/(CE) = 2/(2+2sqrt(3)) = 1/(sqrt(3)+1)=(sqrt(3)-1)/2##
Angle ##/_theta## can be determined using an inverse function ##tan^(-1)()## or as it is often expressed ##arctan()##:
##/_theta = arctan((sqrt(3)-1)/2)~~0.350879411 rad##
Area of triangle ##Delta EAD## can be calculated using the length of its base ##AD## and altitude ##DC##:
##S_(EAD) = 1/2*AD*DC = 1/2*2*2 = 2##