How do I convert the polar equation r=10 sin theta to its Cartesian equivalent?

Cartesian coordinates also known as Rectangular coordinates are defined in terms of ##x## and ##y##. So for this problem ##theta## has to be eliminated/converted using basic foundations described by the unit circle and right triangle trigonometry.
##r=10sin(theta)##
Remember that …
##x=r*cos(theta)##
##y=r*sin(theta)##
##r^2=x^2+y^2##
Multiply both sides of the equation by ##r##
##r*r=10r*sin(theta)##
##r^2=10r*sin(theta)##
##x^2+y^2=10r*sin(theta)##
Use the fact that ##y=r*sin(theta)## to make a substitution.
##x^2+y^2=10y##
##x^2+y^2-10y=0##
The above equation is the Cartesian/Rectangular coordinate equivalent to the given Polar equation.