you need first to try and find the value for both x and y hence initially you set ##y=0## then solve for ##x##. lets try to expand the equation first by opening the bracket.

##y=(x-5)^2##

##Y=X^2-10X+25##

SET ##Y=##0 & SOLVE FOR ##X##.

##0=(X-5)(X-5)##

##X-5=0##

##X=5## ANS. for the x intercept.

SET ##X=0## & SOLVE FOR Y

##Y=(5-5)^2##

##Y=(0-5)^2##

##Y=25##

after setting ##y=0## we have ##x=5## and after setting ##x=0## we have ##y=25## hence ##(025)## and ##(50)##

getting the different values of x and y to plot the equation.

##(025) (116) (29) (34) (41) (50) (61) (74) (89) (916) (1025)##