##sqrt(2x-x^2)/(x-1) x in [0 2]## Let ##a =arc sin ( x – 1 ) in [-pi/2 pi/2]##. Then ##sin a = x-1 in [-1 1] to x in [0 2]##. The given expression ##cot a = cos a/sin a=sqrt (1-sin^2a)/sin a=sqrt(1-(x-1)^2)/(x-1)=sqrt(2x-x^2)/(x-1)##
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