Use the Cartesian form.

The period for the graph is ##(2pi)/2=pi##.

In one half period ##theta in [-pi/4 pi/4] r>=0; r<0##. for the other half
##theta in (pi/4 pi/2]##. In the double period theta in [0 2pi] two
loops are created.
The cartesian form of the given equation is
##(x^2+y^2)sqrt(x^2+y^2)=9(x^2-y^2)## that befits the graphic utility
that is readily available here.
graph{(x^2+y^2)^1.5-8(x^2-y^2)=0 [-10 10 -5 5]}