Please see below. ##(tany+coty)/cscy## = ##(siny/cosy+cosy/siny)xx1/(1/siny)## = ##(sinyxxsiny+cosyxxcosy)/(sinycosy)xxsiny## = ##(sin^2y+cos^2y)/(cancelsinycosy)xxcancelsiny## = ##1/cosy## = ##secy##
Your email address will not be published. Required fields are marked *
Comment *
Name *
Email *
Website
Save my name, email, and website in this browser for the next time I comment.
Δ