Problem 3.4 (Octave Levenspiel) A 10-minute experiment

Problem 3.4 (Octave Levenspiel)
A 10-minute experimental run shows that 75% of liquid reactant is converted to product by a half-order rate. What would be the fraction converted in a half-hour run?Problem 3.6 (Octave Levenspiel) After 8 minutes in a batch reactor reactant (CA0 = 1 mol/L) is 80% converted; after 18 minutes conversion is 90%. Find a rate equation to represent this reaction.Problem 3.11 & 3.12 (Octave Levenspiel) Aqueous A at a concentration of CA0 = 1 mol/L is introduced into a batch reactor where it reacts away to form product R according to stoichiometry A ( RThe concentration of A in the reactor is monitored at various times as shown below:Time min CA mol/m3
0 1000
100 500
200 333
300 250
400 200For CA0 = 500 mol/m3 find the conversion of reactant after 5 hours in the batch reactor.Find the rate expression for the reaction.1 Problem 3.4 (Octave Levenspiel)
A 10-minute experimental run shows that 75% of liquid reactant is converted to product by a half-order rate. What would be the fraction converted in a half-hour run?Problem 3.6 (Octave Levenspiel) After 8 minutes in a batch reactor reactant (CA0 = 1 mol/L) is 80% converted; after 18 minutes conversion is 90%. Find a rate equation to represent this reaction.Problem 3.11 & 3.12 (Octave Levenspiel) Aqueous A at a concentration of CA0 = 1 mol/L is introduced into a batch reactor where it reacts away to form product R according to stoichiometry A ( RThe concentration of A in the reactor is monitored at various times as shown below:Time min CA mol/m3
0 1000
100 500
200 333
300 250
400 200For CA0 = 500 mol/m3 find the conversion of reactant after 5 hours in the batch reactor.Find the rate expression for the reaction.1
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