What is the perimeter of a right triangle with a leg of 10 units and a hypotenuse of square root of 127 units?

The perimeter is ##10+3sqrt{3}+sqrt{127}## units.
The hypoteneuse squared is 127. One leg squared is 100. The other leg squared must be the difference ##127-100=27##. Thus the length of that leg is ##sqrt{27}=3sqrt{3}##.