What is the perimeter of a triangle with corners at (3 4 ) (4 2 ) and (8 7 )?

##the perimeter of triangle is :14.47 units##
##let sides of triangle be aband c##
##perimeter of the triangle is s=a+b+c##
##a=sqrt(5^2+4^2)=sqrt(25+16)=sqrt(41)##
##|a|=6.40 units##
##b=sqrt(5^2+3^2)=sqrt(25+9)=sqrt(34)##
##|b|=5.83 units##
##c=sqrt(2^2+1^2)=sqrt(4+1)=sqrt(5)##
##|c|=2.24 units##
##s=6.40+5.83+2.24##
##s=14.47 units##