How do I find the foci of an ellipse if its equation is x^2/36+y^2/64=1?

##x^2/36+y^2/64=1##
##a^2=64##
##b^2=36##
The center is ##(00)##.
The y-axis is the major axis. We know this because the ##y^2## term has the larger denominator.
We find the foci using the following equation and solving for ##c##.
##c^2=a^2-b^2##
##c^2=64-36##
##c^2=28##
##c=sqrt(2*2*7)##
##c=2sqrt(7)##
The coordinates for the foci are ##(0+-c) -> (0+-2sqrt(7))##