##4##
You may put any power in the argument before the ##ln##:
##lne^4=4lne## (this goes for ##log##’s to any base)
Then since ##e## is the base of the ##ln##-function (##lnx=log_e x##) it follows that: ##lne=log_e e=1## just as ##log_10 10=1##
So: ##lne^4=4*lne=4*1=4##