How do I find the value of sin 45+cos 60?

##(1+sqrt(2))/2##
assuming the values are in degrees
##sin(45)=sin(pi/4)=sqrt(2)/2##
##cos(60)=cos(pi/3)=1/2##
so
##sin(45)+cos(60)=sqrt(2)/2 + 1/2##
##=(1+sqrt(2))/2##