The perimeter of a football field rink is 346 yards. If the length is 14 yards more than 2 times the width what are the dimensions?

##l=120yds##
##w=53yds##
A football field resembles as a rectangle.
The perimeter of a rectangle can be determined by the equation:
##P=2l+2w rarr## equation 1
where:
##P rArr##perimeter
##l rArr##length
##w rArr## width
Converting the given to an algebraic expression gives us:
##color(red)l=14yds+2w rarr##equation 2
Using this expression we can replace ##color(red)l## from equation 1 and come up with a formula that would determine the value of the width.
From equation 1 we have:
##P=2color(red)l+2w##
##P=2(color(red)(14yds+2w))+2w##
##rarr##simplifing the equation gives us
##color(blue)P=28yds+6w##
then
##color(blue)(346yds)=28yds+6w##
##6w=346yds-28yds##
##6w=318yds##
##w=(318yds)/6##
##w=53yds##
Then to find the length simply substitute the value of the width to the equation 2.
##l=14yds+2w##
##l=14yds+2(53yds)##
##l=120yds##
##:.## the dimension of the field is ##120yds## by ##53yds##