How do I graph the quadratic equation y=(x-4)^2-6?

This is a parabola in the form of
##y = (x – h)^2 + k##
where ##(h k)## is the parabola’s vertex.
For this particular equation the vertex is at ##(4 -6)##
The sign of ##x^2## is positive so we have a parabola opening upward.
As a quadratic equation though substitute specific values for X (or Y) and compute for the value of Y (or X) to get specific points of the graph.