There are 31536000 seconds in a year. This is just a series of conversion factors. 1 year ##=(365 days)/(1 year)xx(24 hrs)/(1 day)xx(60 min)/(1 hr)xx(60 sec)/(1 min)## […]
##4m/s^2[forward]## Recall that Newton’s ##2^nd## Law is given by the formula: ##color(blue)(|bar(ul(color(white)(a/a)F_net=macolor(white)(a/a)|)))## where: ##F_net=##sum of all forces acting on the object ##m=##mass ##a=## For this problem […]
We know that for an ideal pendulum time period ##T## is given by the expression ##T=2pisqrt(L/g)## where ##L## is the length of the pendulum and ##g## […]
##T=823.9N## For the fundamental frequency: ##f=(1)/(2L)sqrt((T)/(m))## ##L## = length ##T## = tension ##m## = mass per unit length. ##sqrt((T)/(m))=2Lf## ##T/m=4L^2f^2## ##T=4L^2f^2m## ##T=4xx0.7^2xx261.6^2xx0.0043/0.7## ##T=823.9N##