Published by admin on September 15, 2020 ##x=sqrt(10a)/2## (Assuming ##log = log_10##) ##2log_10(2x) = 1+log_10 a## ##2log_10 2x – log_10 a =1## ##2log_10 2x – 2log_10 a^(1/2) =1## ##2log_10((2x)/sqrt(a)) =1## ##log_10((2x)/sqrt(a)) =1/2## ##(2x)/sqrt(a) […]