Published by admin on September 15, 2020 ##ln(a^20/b^4)## or ##4ln(a^5/b)##. ##20lna=lna^20## by the rule ##bloga=loga^b##. Similarly ##4lnb=lnb^4## by the same rule. So now we have ##20lna-4lnb=lna^20-lnb^4##. Now using the rule ##loga-logb=log(a/b)## we can […]