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##60## ##square units## I have two solutions for you using the formulas ##A=1/2*base*height=1/2bh## -and using – ##A=sqrt(s(s-a)(s-b)(s-c))## where: ##a b and c =>## sides of the […]

The building is (approximately) ##62## feet tall. ##b/d = tan(42^@) = 0.900404## ##color(white)(XXX)rarr d = b/0.900404## ##(40+b)/d = tan(56^@) = 1.482561## ##color(white)(XXX)rarr 40+b = (b/0.900404)xx1.482561## ##color(white)(XXX)rarr […]

##(sinx cosx) / (sinx – cosx) = cosx – [(cosx) / ( 1 – tan x)]## ##(sinx cosx) / (sinx – cosx) = cosx – {(cos […]

##1.931m^2## The formulas for the area of a circle with diameter ##d## and the area of a square with side length ##d## are; ##A_circle = pi […]

Working with the left hand side ##((1+cosx)+(1-cosx))/((1-cosx)(1+cosx))## ##(1+cosx+1-cosx)/(1-cos^2x)## ##2/sin^2x## ##2csc^2x## which is equal to the right hand side

12 is dodecagon 11 is hendecagon also undecagon or endecagon

##A= 572.6 inches^2## Area of circle using diameter##=1/4pid^2## ##d=27## ##A=1/4pi(27)^2## ##A=1/4pi(729)## ##A=(2290.22104447)/4## ##A = 572.555261117 inches^2## ##A = 572.6 inches^2##

Since ##180^circ=pi## radians ##72^circ cdot {pi}/{180^circ}={2pi}/5## radians I hope that this was helpful.

See below ##cos theta/(1-sin theta) + cos theta/ (1+sin theta) = 4## ##(cos theta (1+sin theta)+cos theta(1-sin theta))/((1-sin theta)(1+sin theta)) =4## ##(cos theta + sin theta […]