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see below Left Side: ##=(sinhx/coshx)/(coshx-(sinhx*sinhx/coshx)## ##=(sinhx/coshx)/(coshx-sinh^2x/(coshx))## ##=(sinhx/coshx)/((cosh^2x-sinh^2x)/(coshx))## ##=sinhx/coshx * coshx/(cosh^2x-sinh^2x)## ##=sinhx/(cosh^2x-sinh^2x)## ##=sinhx/1## ##=sinhx## ##=## Right Side

Pyramid’s volume is ##56/3## Let they be ##A(8;5);B(6;7);C(5;1);h=8## First you would calculate the area of the triangle ABC by getting the lenght of a side: ##AC=sqrt((x_C-x_A)^2+(y_C-y_A)^2)=sqrt((5-8)^2+(1-5)^2)=sqrt(9+16)=5## […]

Pentagon is a polygon with ##5## sides and ##5## vertices. This is a definition. The word penta means five.

##r=2(3 cos theta – 4 sin theta )##. Graph is inserted. The conversion formula is ##(x y)=r(cos theta sin theta)## So the polar equation is (r […]

See proof in explanation. ##(sin^2 x)/(cos^2 x + 3cosx + 2) =(1-cosx)/(2+cos x) ## Start with the left hand side: ##(1-cos^2 x)/((cos x+1)(cos x + 2)) […]

##1/(sinxcosx)-cosx/sinx=tanx## ##1/(sinxcosx)-cosx/sinx(cosx/cosx)=tanx## ##1/(sinxcosx)-cos^2x/(sinxcosx)=tanx## ##(1-cos^2x)/(sinxcosx)=tanx## ##sin^2x/(sinxcosx)=tanx## ##sinx/cosx=tanx## ##tanx=tanx##

##SA=lw+lsqrt(h^2+(w/2)^2)+wsqrt(h^2+(l/2)^2)## The surface area will be the sum of the rectangular base and the ##4## triangles in which there are ##2## pairs of congruent triangles. Area […]

The area of circle is ##314.16## square inches and circumference is ##62.832## inches. Area of a circle with radius ##r## is given by ##pir^2## and circumference […]

The Inverse Sine Function is denoted by ##arc sin ## or ##sin^-1## and is defined by ##arc sin x=theta x in [-11] iff sin theta=x theta […]