Published by admin on September 15, 2020 ##color(white)(xx)12sqrt3## ##color(white)(xx)sqrt3/2a=h## ##=>sqrt3/2a=6## ##=>color(red)(2/sqrt3*)sqrt3/2a=color(red)(2/sqrt3*)6## ##=>a=(2color(blue)(*sqrt3))/(sqrt3color(blue)(*sqrt3))*6## ##=>a=4sqrt3## ##color(white)(xx)A=(ah)/2## ##color(white)(xxxx)=6*4sqrt3/2## ##color(white)(xxxx)=12sqrt3##