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##240^o## has a reference angle of ##60^o## as indicated in the image below. A ##60^o## angle is a basic angle from one of the common triangles: […]

##sec^2(pi/3) = 4## ##sec(pi/3) = 1/cos(pi/3)## ##color(white)(XXXX)= 1/(1/2) = 2## ##sec^2(pi/3) = 2^2 = 4##

##x=45^@## ##sin2x-1=0## ##sin2x=1## ##sin2x=sin90^@## ##2x=90^@## ##x=45^@##

The can of corn would be in the shape of a cylinder. Since we are looking at capacity we will want to find the volume. ##V […]

##-60## A right-angled triangle with hypotenuse ##1## and one side ##sqrt(3)/2## has the third side of length ##1/4## by Pythagoras. Draw a unit circle centred on […]

C. ##y= sinx## We need to look for asymptotes here. Whenever there are asymptotes the domain will have restrictions. A: ##y= cotx## can be written as […]

What is ##(5pi)/12## half of? It is half of its double: ##2 xx (5pi)/12 = 2/1*(5pi)/12 =(5pi)/6## ##sin(1/2x) = +-sqrt((1-cosx)/2)## We know that ##(5pi)/12## is in […]

##sin120=sqrt(3)/2## ##cos120=-1/2## ##tan120=-sqrt(3)## ##ctg120=-sqrt(3)/3## ##sec120=-2## ##csec120=(2sqrt(3))/3## To calculate ##sin120## and ##cos120## you can use the reduction formula which says that ##sin(180-x)=sinx## and ##cos(180-x)=-cosx## Rest of the […]

x=n##Pi##+##(-1)^nPi/6##…………general solution x=##Pi/6## if x ##in## [02##Pi##] x=n##Pi##+##(-1)^nalpha## is the general solution of ##sinx=sin alpha## here ##alpha=Pi/6## and n=01234………so on (or n is the number of […]