##b=1.76## ##c=10.15## Using your data we can plot the following triangle: Using trigonometry we have: ##b/a=tan(10^o)## with ##a=10## ##b=1.76## Also: ##a=c*cos(10^o)## ##c=10.15##
Since ##cos2x=cos^2x-sin^2x=1-2sin^2x=2cos^2x-1## and ##sin2x=2sinxcosx## then: ##(1+2cos^2x-1)/(2sinxcosx)=cotxrArr## ##(2cos^2x)/(2sinxcosx)=cotxrArr## ##cosx/sinx=cotxrArr## ##cotx=cotx##.
Area of the rectangle ##=55125 sqft## Length of the rectangle ##l=315## and width ##w=175## So Area of the rectangle ##=l timesw=315times 175=55125 sqft##
Apply the angle-sum identity for cosine to ##cos(x+x)##. The identity needed is the angle-sum identity for cosine. ##cos(alpha + beta) = cos(alpha)cos(beta) – sin(alpha)sin(beta)## With that […]
Circumference##=48pi## meters The circumference of circle is calculated by the formula: ##Circumference=2pir## So if ##radius=r=24## meters ##Circumference=2picolor(red)((24))=48pi## meters