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Convert to sine and cosine … ##tan(pi/6)=sin(pi/6)/cos(pi/6)=(1/2)/(sqrt3/2)=1/sqrt3=sqrt3/3## hope that helped

The circumference ##L## is ##L=2*pi*r=>2*r=L/pi## but ##2r## is the diameter of the circle let say ##d## hence ##d=L/pi##

##48^@## Complementary angles are angles that when added equals to ##90^@##. To find the complementary angle of ##42^@## simply subtract it from ##90^@##.

##(3pi)/8## radians ##= 67.5^@## The standard ratio is ##(180^@)/(pi radians)## ##(3pi)/8 radians## ##color(white)(XXX)=(3 cancel(pi))/8 cancel radians xx (180^@)/(cancel(pi) cancel( radians)## ##color(white)(XXX)=(540^@)/8## ##color(white)(XXX)=67.5^@##

4r^2 surface area of sphere = ## 4 pi*r^2##

##30^o and 60^o are angles of one of the standard triangles## ##sin(30^o) = 1/2## ##cos(30^o) = sqrt(3)/2## ##sin(60^o) = sqrt(3)/2## ##cos(60^o) = 1/2## So ##sin(60^o)*cos(30^o) + […]

##32## Given that ##AB and C## are collinear (lying in the same straight line) and B is in between A and C and ##AB=15 AC=47## ##=> […]

Side length ##= 17## ##cm ## Area of a square ##= s^2## where ##s =## side length we have ##289 = s^2= s xx s## ##17 […]

##200cm^3## The volume of any pyramid is ##1/3xxbase areaxx_|_ht## so vol## =1/3xx10xx10xx6## l## =1/cancel(3)xx10xx10xxcancel(6)^2## ##=200cm^3##