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The related acute is an acute angle (##

##360 div 12 = 30## sides The only number that stays the same for the angles of all polygons is that the sum of the exterior […]

I use www.desmos.com/calculator. You just type the equation. All that I did was type in ##r = 2 + 4sin(theta)## and it plotted this graph:

Multiply the left side in the numerator and denominator by 1-tanx and simplify to get the answer: ##(1-tanx)^2 / (1-tan^2 x)## =##(1+tan^2x -2tanx)/(1- (sin^2x/cos^2x)## = ##(sec^2x […]

The solutions are ##(5pi)/4## and ##(-pi)/4## The first solution has a direct answer because ##arc sin{sin(z)}=z## with every number ##z## so ##(5pi)/4## is a solution. Its […]

Very Carefully… The top portion of this fraction is a difference of 2 squares meaning ##sin^2(x)-cos^2(x)=(sin(x)+cos(x))(sin(x)-cos(x))## so ##(sin^2(x)-cos^2(x))/(sin(x)+cos(x))=((sin(x)+cos(x))(sin(x)-cos(x)))/(sin(x)+cos(x))## ##=sin(x)-cos(x)##

Two acute angles can be verticaladjacentcomplementary. They cannot be supplementary. Two angles ##/_A## are vertical (formed by two intersecting lines) and acute (smaller than ##90^o##). Angles […]

see below Use formula: ##cosh x=(e^x+e^-x)/2 and sinh x = (e^x-e^-x)/2## Right side:##=cosh^2x+sinh^2x## ##=((e^x+e^-x)/2)^2 +((e^x-e^-x)/2)^2## ##=(e^(2x)+2+e^(-2x))/4 + (e^(2x)-2+e^(-2x))/4## ##=(e^(2x)+2+e^(-2x)+e^(2x)-2+e^(-2x))/4## ##=(2e^(2x)+2e^(-2x))/4## ##=(2(e^(2x)+e^(-2x)))/4## ##=(e^(2x)+e^(-2x))/2## ##=cosh (2x)## ##=## Left […]

You can use some identities to make this easier. ##cos(50^o) = cos(-50^o) = -cos(130^o)## due to ##cos(x) = cos(-x)## ##cos(x) = -cos(x+pi)## Thus you have: ##tan(130^o) […]